Question
Prove the identity.$$\frac{\tan x-\sin x}{2 \tan x}=\sin ^{2} \frac{x}{2}$$
Step 1
Step 1: We start with the left-hand side of the equation and rewrite $\tan x$ as $\frac{\sin x}{\cos x}$: $$\frac{\tan x-\sin x}{2 \tan x} = \frac{\frac{\sin x}{\cos x}-\sin x}{2 \frac{\sin x}{\cos x}}$$ Show more…
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