Prove the identity.
$ \sinh 2x = 2 \sinh x \cosh x $
$\sinh 2 x=\sinh (x+x)=\sinh x \cosh x+\cosh x \sinh x=2 \sinh x \cosh x$
We know that either the two experts e to the negative two x over, too. We can write this as two times. Each of the two acts preceded the Ark's most axe, my seat of the X minus axe. I wanna see the negative two acts. Remember, this is all divisible by four, two times E. The two acts runs E to the negative. Two acts over four gives us each of the two acts mines either the negative two acts and with the two and four, this just becomes 1/2.