Question
. Prove the polarization identity,$$\|\mathbf{u}+\mathbf{v}\|^2-\|\mathbf{u}-\mathbf{v}\|^2=4(\mathbf{u} \cdot \mathbf{v})$$
Step 1
The norm squared of a vector is given by the dot product of the vector with itself. Therefore, \[ \|\mathbf{u} + \mathbf{v}\|^2 = (\mathbf{u} + \mathbf{v}) \cdot (\mathbf{u} + \mathbf{v}). \] Show more…
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