Question
Prove the stated theorem.If a line through the center of a circle bisects a chord other than a diameter, then it is perpendicular to the chord. See Figure 6.38 on page 289.
Step 1
The line through the center O bisects the chord AB at M, which means AM = MB. Show more…
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Prove the stated theorem. If a line is drawn through the center of a circle perpendicular to a chord, then it bisects the chord and its minor arc. See Figure 6.37 on page 288 (NOTE: The major arc is also bisected by the line.)
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PROVING A THEOREM Write a proof of the In center Theorem (Theorem 6.6$)$ . Given $$ \begin{array}{l}{\triangle \mathrm{ABC}, \overline{\mathrm{AD}} \text { bisects } \angle \mathrm{CAB}} \\ {\frac{\mathrm{BD}}{\mathrm{BD}} \text { bisects } \angle \overline{\mathrm{CA}}} \\ {\text { and } \overline{\mathrm{DG}} \perp \overline{\mathrm{CA}}}\end{array} $$ Prove The angle bisectors intersect at $\mathrm{D},$ which is equidistant from $\overline{\mathrm{AB}}, \overline{\mathrm{BC}},$ and $\overline{\mathrm{CA}}$ .
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$\overline{\mathrm{AB}}$ is a chord of circle $\mathrm{E},$ and $\mathrm{C}$ is the midpoint of $\overline{\mathrm{AB}}$. Prove that $\overrightarrow{\mathrm{EC}}$ is the perpendicular bisector of chord $\overline{\mathrm{AB}}$.
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