Question
Prove Theorem 12.4: Let $f$ be a symmetric bilinear form on $V$ over $K$ (where $1+1 \neq 0$ ). Then $V$ has a basis in which $f$ is represented by a diagonal matrix.
Step 1
A bilinear form $f$ on a vector space $V$ over a field $K$ is called symmetric if $f(u, v) = f(v, u)$ for all $u, v \in V$. Show more…
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Prove Theorem 12.5: Let $f$ be a symmetric bilinear form on $V$ over $\mathbf{R}$. Then there exists a basis of $V$ in which $f$ is represented by a diagonal matrix. Every other diagonal matrix representation of $f$ has the same number $\mathbf{p}$ of positive entries and the same number $\mathbf{n}$ of negative entries.
Prove Theorem 12.3: Let $f$ be an alternating form on $V$. Then there exists a basis of $V$ in which $f$ is represented by a block diagonal matrix $M$ with blocks of the form $\left[\begin{array}{rr}0 & 1 \\ -1 & 0\end{array}\right]$ or $0 .$ The number of nonzero blocks is uniquely determined by $\left.f \text { [because it is equal to } \frac{1}{2} \operatorname{rank}(f)\right].$
Let $[f]$ denote the matrix representation of a bilinear form $f$ on $V$ relative to a basis $\left\{u_{i}\right\} .$ Show that the mapping $f \mapsto[f]$ is an isomorphism of $B(V)$ onto the vector space $V$ of $n$ -square matrices.
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