00:01
First, we need to balance reaction.
00:10
It helps to start with the diatomic atom first.
00:13
So for every one oxygen, there's two mercury oxides.
00:17
That means that there's two mercury atoms.
00:21
In b, if we start with 45 .5 grams of hco.
00:30
First, let's find the math of mercury.
00:32
So that means dividing by the molar math of hgo, which is 216 .559.
00:39
In every one mole.
00:45
Notice that the coefficients are equal.
00:49
There's two of each.
00:50
So for every two moles of mercury, there are two moles with mercury oxide.
00:58
And then finish by multiplying by the molar mass of mercury, which is 200 .59 grams in every one mole of mercury.
01:11
Check the units, grams of mercury oxide, moles of mercury oxide, moles of mercury, we're left with grams of mercury, the value of 42 .1 grams of mercury metal...