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Pure phosgene gas $\left(\mathrm{COCl}_{2}\right), 3.00 \times 10^{-2}$ mol, was placed in a 1.50 -L container. It was heated to $800 \mathrm{K}$, and at equilibrium the pressure of $\mathrm{CO}$ was found to be 0.497 atm. Calculate the equilibrium constant $K_{P}$ for the reaction

$$K_{p}=3.31$$

Chemistry 102

Chapter 14

Chemical Equilibrium

Carleton College

Drexel University

University of Kentucky

Lectures

10:03

In thermodynamics, a state of thermodynamic equilibrium is a state in which a system is in thermal equilibrium with its surroundings. A system in thermodynamic equilibrium is in thermal equilibrium, mechanical equilibrium, electrical equilibrium, and chemical equilibrium. A system is in equilibrium when it is in thermal equilibrium with its surroundings.

00:54

In chemistry, chemical equilibrium (also known as dynamic equilibrium) is a state of chemical stability in which the concentrations of the chemical substances do not change in the course of time due to their reaction with each other in a closed system. Chemical equilibrium is an example of dynamic equilibrium, a thermodynamic concept.

04:58

Pure phosgene gas (COCl $_…

04:02

The equilibrium constant $…

05:58

02:06

A 2.00-L container at $463…

her goal for this problem is to find the KP value for this balanced chemical equation. In order to do so, the first thing we need to do is find the initial pressure of C o. C L to r product. So in order to do so, we will use the equation. PV equals and are tee. And this is the ideal gas equation Since since we want to find the initial pressure of Seo Seals sea OOCL too, we can isolate WPI by rearranging equation to be as follows. So out of her given information, we were given all of the information you need to find the initial pressure. ASIO seal too. So we were told that the number moles coc l two was three times 10 to the native to are is it constant? It's the ideal gas constant that we know to be 0.0 8 to 1 and the temperature is 800 Calvin. We were also told that the volume was 1.50 leaders and doing all this out, you find that the initial pressure of c o. C. L two is 1.314 a t m. We were also told in the problem that at equilibrium the pressure A CEO was equivalent to 0.497 ATM. So now that we know the initial pressure of our product and what the partial pressure of Seo is at equilibrium, we can make in ice table to find all the values we need to find the KP of this balance equation. So in order to make the ice table, I went to rewrite the equation and we'll have the initial change. An equilibrium values strong line here so we can separate them. Initially, we have none here, none here. But we know that the partial pressure initially of C O. C. L two is what we calculated here to be 1.314 a. T m. We also know are at equal a real value for the change has to be 0.497 Since we have zero point where 97 at equal. Aram These are positive change values, but that also means that we see and negative subtraction 0.497 on the product side, which leaves us with zero point 817 a. T. M. For partial pressure of C O. C. L. Two at equilibrium. So now that we know these values were able to find KP taking the partial pressure at equilibrium of our products, we know to be zero point 817 from our ice table. Over reacted number one carbon monoxide at equilibrium multiplied by direct number to Corinne at equal room and calculated out, this comes out to be three point 31 as our KP equilibrium constant.

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