00:01
I'm going to use the quadratic formula to solve this.
00:05
And in order to do that, it has to be in standard form.
00:08
So i'm going to subtract 20q from both sides.
00:16
And that's going to leave me with 4q squared minus 20q plus 6 equals 0.
00:27
And now that i have it in standard form, my a x squared plus bx plus c, i can identify my values.
00:33
So the a value is the coefficient of my squared term, which is 4.
00:39
My b value is the coefficient of my linear term, q, which here is negative 20.
00:47
And my c term is my constant, which here is 6.
00:51
Then i am going to write down the quadratic formula so that i have it as a reference.
00:58
X equals negative b plus or minus the square root b squared minus 4a c all over 2a i did i did sing that all right so now i'm going to substitute my values x equals negative b plus or minus the square root b squared minus 4 a c all over 2 a all right so negative times a negative is a positive plus 20 squared negative is 400 minus 4 24, 24 times 4 is 96, and 2 times 4 is 8.
02:05
So, 400 minus 96 is, what, 304? it is.
02:28
I did it in my head correctly.
02:32
Yay me.
02:34
Alright, over 8.
02:36
So now i'm going to factor 304 because i have a feeling that it's got a perfect square, at least one of them that i can factor out.
02:47
So i'm going to factor 304.
02:50
We'll do two times 152.
02:56
Do two times 76, which is two times 38, two times 19.
03:16
There we go.
03:17
There's prime.
03:18
So i have this...