Question
Quadrilateral ABCD has vertices A(4, 9), $\mathrm{B}(8,-3), \mathrm{C}(2,-7),$ and $\mathrm{D}(-2,5)$How do you know?
Step 1
The midpoint formula is given by $\frac{(x_1+x_2)}{2}$, $\frac{(y_1+y_2)}{2}$. For AC, the midpoint is $\left(\frac{4+2}{2}, \frac{9-7}{2}\right) = (3,1)$. For BD, the midpoint is $\left(\frac{8-2}{2}, \frac{-3+5}{2}\right) = (3,1)$. Show more…
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