Question
Quelle est l'enthalpie molaire de formation de référence de $\mathrm{FeO}$ à la température de $800 \mathrm{~K}$ ?
Step 1
The formation reaction is: \[ \text{Fe (s) + } \frac{1}{2} \text{O}_2 \text{(g) } \rightarrow \text{FeO (s)} \] Show more…
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Determine the standard heat of formation for FeO(s) given the following values for the heats of reaction at 25°C and 1 atm for the following reactions: Fe(s) + 3/2 O2(g) -> FeO(s) ΔH = -822 kJ/mol 2 Fe(s) + 1/2 O2(g) -> Fe2O3(s) ΔH = -84.1 kJ/mol
From the following data at 298.15 K, calculate the standard enthalpy of formation of FeO(s) and of Fe2O3(s): ΔrH⊖ (kJ mol-1) Fe2O3(s) + 3C(graphite) → 2Fe(s) + 3CO(g) 492.6 FeO(s) + C(graphite) → Fe(s) + CO(g) 155.8 C(graphite) + O2(g) → CO2(g) -393.51 CO(g) + 1/2O2(g) → CO2(g) -282.98
The reaction of $2 \mathrm{~mol} \mathrm{Fe}(\mathrm{s})$ with $1 \mathrm{~mol} \mathrm{O}_{2}(\mathrm{~g})$ to make $2 \mathrm{~mol} \mathrm{FeO}(\mathrm{s})$ gives off $544 \mathrm{~kJ} .$ Calculate the enthalpy change that accompanies the formation of $100.0 \mathrm{~g} \mathrm{FeO}$.
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