00:01
Okay, so when you're dealing with acid, chemized, hydration, and hydroboration oxidation, the biggest thing you got to remember is that we're going to add that bromine group to the less substituted side.
00:12
And that's why it allows us to create only one product.
00:15
So, for example, if we were to create a product or a react, sorry, a reactant, not a product, like this, two, three, like this, it allows us to really place it on either.
00:39
Side.
00:46
So that way we have this bromium that's added to either side and we can form a product like that we see here.
00:56
I'm just pausing because i think there's multiple ways we can approach this that i just realized.
01:01
So that's one way you could solve this.
01:03
Or, oh no, that is correct.
01:10
I was thinking you could put it like that.
01:13
But what's our issue if i were to do that? so right here we'd have five carbon bonds.
01:19
And so that'd be incorrect.
01:20
So just be careful there.
01:21
I almost fell to that one...