questions-1-3-refer-to-the-following-scenario-image-is-not-available-to-copy-an-explorer-travels-30-

Question

Questions 1-3 refer to the following scenario:
IMAGE IS NOT AVAILABLE TO COPY
An explorer travels 30 $\mathrm{m}$ east, then 20$\sqrt{2} \mathrm{m}$ in a direction $45^{\circ}$ south of east, and then 140 $\mathrm{m}$ north.
What is the distance traveled by the explorer?
(A) 167.2 $\mathrm{m}$
(B) 169 $\mathrm{m}$
(C) 170 $\mathrm{m}$
(D) 198.2 $\mathrm{m}$

Sachin Rao · Accepted Answer

in this problem, we have given an explorer travel step in Middle East Demeter east and then 22 m in the direction of 45 degrees south of east. This is east, west, north and south. So not a single is 45 degree and the stances 22 and then travels 1 40 m in the north. Direction 1 14 m in the north direction. What is the distance traveled? So we will add all the distances. I don&#x27;t understand what they called you. 30 plus 22 plus 1. 40. So we will add these three. This is equal to 30 plus 20 into two. One plus 1 40. So this is a cold 1. 98 point 28 m. Now we check our options. Option B with the correct option. Distance traveled by the explorer is the holder 1 98.2 m. Thank you.

Salamat Ali · Answer

original lost e. So a ritual lost to be here. Izzy called thio Displacement Displacement to do wait it by dime. So displacement here divided time all the time. The displacement we found earlier is 1 30 So 1 30 in the total time is 260 seconds. So, are you ready this week? It zero point father meter per second. So the answer is a

Mayukh Banik · Answer

there&#x27;s copy the diagram at five. And at 1 25 Let&#x27;s say this is 101 50 and this is 100 and then we have we have 50 and he is a 25. The God travelers like this and this is five second. If we do a straight line from 25 and come down here looking at the diagram, this point will be four seconds. So part A. The answer is four second for part B. Where was the card? One second. So figure out where one second is and then draw a straight line up to one second. Actually, one second would be a little area according to the diagram. According to diagram, it looks like the car is at one second at one second, but be at one second. The car is that 100 meted mark, although this doesn&#x27;t look like this from the diagram but concert, the diagram and the numbers. Who makes

Ebenezer Ankomah · Answer

So we have trade their tests to find the resultant vector. The first victor victor one. Yes, 24 m 36 36 degrees north of east. 2nd Victor Victor Too. It is 18 m 37 degrees east. Oh moth. In the 3rd Victor 26 m Territory degrees west off. So so to find a resultant victim graphically, what you need to do is first draw your craft. So I have my mouth too. And my east. Who? So for the first vector, I&#x27;m using a red matter. It states is degrees northeast. So I missed. It takes these degrees think for me test and I&#x27;m getting some something like this. Yeah, like this. Then the 2nd victor. If 80 m 37° East of north, It&#x27;s my measurement takes 7° east of law, et me tests. And uh it&#x27;s going this way in the last victor is 33° west of South. So obviously to come down And that&#x27;s one is 26 m. Okay, so these are my victories. So now the resultant vector? Yes. The distance from the tip of the first victor to the tape of your last victor. So when you measure the length, both this line that will give you your resultant vector. So when you draw this up to skill, you&#x27;re resultant vector. We are if 17.4 it tastes. The angle is 22.5. The green. No. Oh yes!

Averell Hause · Answer

it&#x27;s here. The man is walking 30 meters east and we have 40 meters north. In order to find the displacement rather the distance from the origin, we can simply use peptide. Green&#x27;s theorem get called this X where X would be equal, then to the square root of the 30 meters quantity squared plus 40 meters, quantity squared and excess than equaling 50 meters. If his total distance traveled, we could say equaling 40 meters plus 30 meters Equalling that, of course, 70 meters and the different than the difference between the total distance traveled and the displacement would be 70 meters. Of course, minus 50 meters, 20 meters. So be that is the end of the solution. Thank you for watching.

Averell Hause · Answer

actors vector a vector be. We know that Victor is gonna be 12.0 meters. This is gonna be 20 degrees west of north and then we have Hector B 20.0 meters. Now, this is gonna be 40 degrees north of east and we&#x27;re trying to find our which is essentially equaling a plus B. So we can then say that here. Ace of X a sub y beasts of ex beasts of why Ace of X is going to be equaling 12.0 meters. Co sign Now here is the difficulty. Here we have 20 degrees west of north. We&#x27;re in the second quadrant, so this is gonna be negative. 12.0 years co sign of 20 degrees west of north is the same as saying actually 70 degrees north of west. So in negative 12.0 meters co sign of 70 degrees. This is equally negative 4.104 meters and then we have a sub y 12.0 meters sign of 70 degrees. We&#x27;re in the second quadrant, so we know that this is gonna be positive. 11.27 meters. Beasts of X now 40 degrees north of east were in the first quadrant. So we&#x27;re gonna have a positive X and a positive. Why? So this would be 20.0 meters co sign of 40 degrees, 20.0 meters sign of 40 degrees for the X component. We have 15.32 meters for the white component. We have 12.85 meters and finding our sub x. This is simple. We just add these two together so it would be 15.32 minus four point 104 An arse of X is equaling 11. Rather it positive 11.21 meters. My apologies are sub y is equal ing again you use Add these up 11.27 plus 12.85 and we have our supply equaling 24 0.12 meters. Now, at this point, me to find the, um magnitude of the results Inspector so this would be equaling essentially 11.21 meters quantity squared plus 20 4.12 meters quantity squared, all raised to the 1/2 power. So the sum of the squares is raised to the 1/2 power. This is equaling 26.59 meters. This would be our magnitude for our resulted vector. Now our direction would be equaling. Are 10 of the wind component divided by the X component and in this case we have 24.12 meters, divided by 11.21 meters. Now this is equaling 65.7 degrees. But going back, we know that here we have positive X component and a positive or component for the results of Vector which actually means that here, we&#x27;re going to be in the first quadrant. So this would be 65.7 degrees north of east. Now, at this point, we can actually this would be our final answer for a part A And now we can go to part B. Where here we have the exact same. However, now Spector a vector B vector A is gonna be equaling 20.0 meters and this would be 40 degrees south of west and then we have 12.0 meters, 20 degrees east of south. And now the way you add these are it is extremely important in the sense that we have to say that the results of Vector is again equaling a plus B explicitly. And when I say explicit me explicitly, I just mean you cannot you cannot say, um be when the community communicative property of, uh of addition doesn&#x27;t apply to vectors. So when we add vectors were adding simply tipped thio tail to tip and we have to add them in the specific order that, um the question is asking for. So here we have four part B again where this process, however, the same ace of X, a sub y beast of ex piece of why and for a ce of ex ah, we have here, it&#x27;s gonna be a 20 20 meters now, 20 meters, we have 40 degrees south of west. So this is actually gonna be in the third quadrant, which means we have a negative X and a negative. Why so negative? 20.0 meters negative, 20.0 meters. And this is gonna be Times Co sign of 40 degrees times sign of 40 degrees. And so this is equaling negative 15.32 meters. This would be negative 12.85 meters. Ah, beasts of X would be 12.0 meters, 20 degrees east of south. So east of south is actually in the fourth quadrant, which means we have a positive X negative y and 20 degrees east of south is actually the same thing as saying 70 degrees south of east. So we can say 12.0 meters times co sign of 70 degrees and then 12 rather negative 12.0 meters sign of 70 degrees. And we can then say that 12.0 meters times co sign of 70 degrees. Ah, this is gonna be equaling 4.104 meters and then negative 12.0 meters sign of 70 degrees. This is equaling. Oh, negative. 11.27 meters. And now we can say our sub X is gonna be equaling negative 15.32 AA plus 4.104 So we have approximately, we can say, uh, negative 11 point 22 meters. And then our sub y is equaling negative. 12.85 minus negative. 11.27 And this is gonna be negative 24.12 meters and we can find the magnitude of the result. Inspector. This would be again. We have negative 11.22 meters quantity squared plus negative 24.12 meters Quantity squared, all raised to the 1/2 power. The so the sum of the squares rate to the 1/2 power. And we have that the result, Inspector Magnitude of the results in fact here is equaling 26.59 meters. This would be our answer for the magnitude to find the direction again. We have a negative Xnegative wise. We&#x27;re gonna be the third quadrant. And this would be our 10 of the U. Y component 24.12 divided by the X component 11.22 And this is giving us 65.7 degrees. So fate of the direction 65.7 degrees south of west. This would be our answer our magnitude and direction of the results, Inspector. For part B, that is the end of the solution. Thank you for watching

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Questions 1-3 refer to the following scenario: I…

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