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Questions 15–17 all refer to the below circuit diagram.If switch $S_{2}$ is connected to point A but switch $S_{1}$ is left unconnected,what is the current through the resistor labeled $R ?$(A) $\frac{9 V_{2}}{R}$(B) $\frac{13 V_{2}}{3 R}$(C) $\frac{3 V_{2}}{13 R}$(D) $\frac{V_{2}}{9 R}$

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Chapter 1

Practice Test 1

Section 1

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in this problem switch as two is connected to Point A&S. one is left unconnected. This results in the right most arm of the circuit with two resistors in parallel being out of the circuit, and we are left with the left most resistant to our and the two resistors in parallel to our in for our in the middle branch of circuit And the Voltage v. two. And we have to find out the current through the sister are. So first we'll find the equivalent resistance so we can see that they couldn't resistance will be the cities of to our our and Parallel combination of two. R. and for our so the covenant resistance is Are equivalent equal to two are plus our plus parallel combination of two R. And four hour. Which can be given by two or in 24 hour. Bye to R. Plus four. So This is three are plus four. Are by sorry four are by three. This gives us 13 are by today. So current given by battery would be equal to voltage battery by equivalent resistance equal to B to buy 13 are by three called to three. We to buy 13. Now we can see that the battery here is in serious with the sisters are so the current through the sister are will be equal to I I will be called to current given by the battery. So the current Through resistor. R is simply three v. 2 by 13. Are this complete solution? Thank you.

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