Question
Questions 44–45 refer to the following circuit below:IMAGE IS NOT AVAILABLE TO COPYHow long will it take for the battery to deliver 300 $\mathrm{J}$ of energy to the circuit?(A) 6 $\mathrm{s}$(B) 12 $\mathrm{s}$(C) 18 $\mathrm{s}$(D) 24 $\mathrm{s}$
Step 1
We can see that there are two resistors in series. The total resistance of resistors in series is given by the sum of their resistances. So, we have $R_{\text{series}} = R_1 + R_2 = 1\, \Omega + 2\, \Omega = 3\, \Omega$. Show more…
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Questions $44-45$ refer to the following circuit below: How long will it take for the battery to deliver 300 $\mathrm{J}$ of energy to the circuit? (A) 6 $\mathrm{s}$ (B) 12 $\mathrm{s}$ (C) 18 $\mathrm{s}$ (D) 24 $\mathrm{s}$
Consider the circuit shown in Fig. $\mathbf{P 2 6 . 6 3 .}$ (a) What must the emf $\mathcal{E}$ of the battery be in order for a current of $2.00 \mathrm{~A}$ to flow through the $5.00 \mathrm{~V}$ battery as shown? Is the polarity of the battery correct as shown? (b) How long does it take for $60.0 \mathrm{~J}$ of thermal energy to be produced in the $10.0 \Omega$ resistor?
Questions $4-8$ refer to the following circuit diagram. How much power is dissipated in the 4$\Omega$ resistor each second? (A) 8 $\mathrm{W}$ (B) 10 $\mathrm{W}$ (C) 16 $\mathrm{W}$ (D) 20 $\mathrm{W}$ (E) 32 $\mathrm{W}$
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