Question
Radius of orbit of satellite of earth is $\mathrm{R}$. Its $\mathrm{KE}$ is proportional to(A) $(1 / R)$(B) $(1 / \sqrt{\mathrm{R}})$(C) $\mathrm{R}$(D) $\left(1 / \mathrm{R}^{3 / 2}\right)$
Step 1
Step 1: The kinetic energy (KE) of a satellite in orbit is given by the equation: \[KE = \frac{1}{2} m v^2\] where \(m\) is the mass of the satellite and \(v\) is its velocity. Show more…
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