00:01
Okay, so you were just introduced to substitution effects and directing groups, right? so you're given three sets of compounds, and all of them have varying degrees of activation, deactivation.
00:22
So in each scheme, you basically just have to figure out which you're going to react or rank them in order.
00:31
Of rate of reaction, right? so deactivated rings are going to be first.
00:38
So number one will be the most deactivated.
00:41
And then we'll go up to four, which will be the most activated.
00:45
So basically you're ignoring the benzene ring.
00:47
You're just looking at the substituents, pretty much, right? so in the first scheme, we have, we have nitrobenzine, we have phenol, we have tonyene, and we have regular benzene.
00:57
So if you look at all of the groups, right? so in this case, we have one deactivating group.
01:06
That's the nitro group.
01:07
And we have two activating groups.
01:09
That's the hydroxyl group and the methyl group.
01:11
And then benzene has an h.
01:12
That's nothing, right? so the deactivated group is going to be number one.
01:18
This is the slowest.
01:19
And then essentially, you have, you have two activating groups and you have benzene.
01:25
So any type of activating group is going to give you a faster, a faster rate to electrophelic aromatic substantiated.
01:32
Then benzene will.
01:33
So by default, benzene's going to be two.
01:37
And then when you're stuck with all of your activated rings, which ring is more active? so you go to page 581 and you look at the classification of substitution effects figure and you look at where hydroxyl is in comparison to alcohol.
01:53
And hydroxyl is much more activating than the alcohol group.
01:56
So tonnuin is going to be jah slower than phenol.
02:00
So phenol is going to be the fastest here.
02:03
So you do the same thing in in b, right? so in this case, you have two deactivating groups.
02:09
You have the chlorine and you have this, this acyl group, this carboxylic acid.
02:14
It's not really an acyl group...