00:01
So for this problem, we need to rank the following sets of substituents according to the con angled pre -log sequence rules.
00:10
So we have a, b, c, d, e, and f.
00:17
So, well, let me move these down.
00:21
So i could write something above it.
00:23
That'll help us out.
00:25
So we are going to start with the highest priority and go to the lowest.
00:36
Priority.
00:40
For a, it goes in this order, the methyl, and then the hydrogen.
00:54
For b, the highest priority would be negative o -c -h -3, then negative o -h, then negative co2h, and then negative -hydrogen.
01:09
For c, the highest priority would start off with negative co2 -ch3, then it'll go to negative co2h, then it goes to negative ch2 -o -h, and then lastly the methyl, negative c -h -3.
01:29
For part d, it starts off with the highest priority being negative c -o -c -h -3, then the next would be negative ch2, ch2oh...