00:01
Let's start this problem by remembering the arrhenius equation, which states that we have some value k, our rate constant, which equals a, e to the negative ea over rt.
00:18
So, when we're working at different temperatures, we'll remember that this value a doesn't change, but values k and t will change.
00:28
Ea, r, and little e, of course, are all constant.
00:30
So let's go ahead and divide these two expressions.
00:34
So let's take k1 over k2, which is going to be equal to a over a, the a's cancel, e to the negative ea over rt1 plus ea over rt2.
01:02
Okay, so let's work through this now and take the natural log.
01:07
Of both sides.
01:09
So natural logarithm gets us k1 over k2.
01:14
The e drops away and we are left with ea, there should be an equal sign in here, equals ea over r, 1 over t2 minus 1 over t1.
01:33
Now let's go ahead and substitute in our values and we find that we get an e2, an e2, e .a.
01:42
133 .76 kilojoules per mole...