Question
Ratio of $\pi$ - and $\sigma$ -bonds in $\mathrm{Ph}$ -COOH will be(a) $5: 3$(b) $3: 5$(c) $3: 16$(d) $4: 15$
Step 1
$\mathrm{Ph}$ stands for phenyl group which is a benzene ring, and -COOH is the carboxyl group. The structure will look like a hexagonal ring (which is the benzene ring) attached to -COOH. Show more…
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Ratio of $\pi$ - and $\sigma$ -bonds in $\mathrm{Ph}$ -COOH will be (a) $5: 3$ (b) $3: 5$ (c) $3: 16$ (d) $4: 15$
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