This is because the square root of a number multiplied by itself gives a rational number.
(a) $\frac{1}{\sqrt{6}}$ becomes $\frac{1*\sqrt{6}}{\sqrt{6}*\sqrt{6}}$ = $\frac{\sqrt{6}}{6}$
(b) $\frac{3}{\sqrt{2}}$ becomes $\frac{3*\sqrt{2}}{\sqrt{2}*\sqrt{2}}$ =
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