Rationalize the difference in boiling points for each of the following pairs of substances:
a. $n$ -pentane $\quad \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} \quad 36.2^{\circ} \mathrm{C}$
$$\begin{array}{c}
\mathrm{CH}_{3} \\
\text { neopentane } \mathrm{H}_{3} \mathrm{C}-\mathrm{C}-\mathrm{CH}_{3} \quad 9.5^{\circ} \mathrm{C} \\\mathrm{CH}_{3}
\end{array}$$
$$\begin{aligned}
&\begin{array}{lr}
\text { b. } \mathrm{HF} & 20^{\circ} \mathrm{C} \\
\text { HCl } & -85^{\circ} \mathrm{C} \\
\text { c. } \mathrm{HCl} & -85^{\circ} \mathrm{C} \\
\text { LiCl } & 1360^{\circ} \mathrm{C} \\
\text { d. } n \text { -pentane } & \mathrm{CH}_{3} \\
n \text { -hexane } & \mathrm{CH}_{3}
\end{array}\\
&\begin{array}{ll}
\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} & 36.2^{\circ} \mathrm{C} \\
\mathrm{SH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} & 69^{\circ} \mathrm{C}
\end{array}
\end{aligned}$$