00:02
In problem 9 .48, we are asked to provide a mechanism for changing all the hydrogens on acetone into deuteriums.
00:13
Now, we are asked to look at the mercury -catalyzed hydrogenation of an alkynes to get an idea of the correct mechanism for this problem.
00:26
At the end of the mercury -catalyzed mechanism, there is the keto -enyl ptotomerism that is present.
00:34
In many ketones.
00:37
I will draw the keto and enol forms below.
00:42
The keto form is more preferred than the email form, and this will be the major product.
01:13
So the keto form is on the left, and the enol form is on the right.
01:18
It is by this mechanism that the deuteriums will be added.
01:24
I will show the electron, the mechanisms with the electron flow below.
01:31
And i will react to them.
01:32
With deuterium.
01:37
So we start out with our keto form and each end of the carbon will have three hydrogens, but i'll only focus on the right side in this problem.
02:00
This molecule will then be reacted with d3o as opposed to h3o and the keto will pick up one of the deuteriums.
02:14
So we have od3, two lone pairs on oxygen and the lone pairs on the keto oxygen will pick up one of the deuteriums attached to the od3.
02:58
So this oxygen will pick up a deuterium leaving its electrons, and this will go back and forth with the next intermediate.
03:13
In the next intermediate, we have the oxygen with a double bond to the carbon.
03:32
That will now have a deuterium.
03:38
And this will have a positive charge.
03:42
We still have the same three hydrogens on the end.
04:03
And this will have another resonant structure, which will help predict the enol form and how the deuteriums are incorporated.
04:37
So the electrons will fold up from our keto form...