Question
Reaction of cyclohexene with mercury(II) acetate in $\mathrm{CH}_{3} \mathrm{OH}$ rather than $\mathrm{H}_{2} \mathrm{O}$ followed by treatment with $\mathrm{NaBH}_{4},$ yields cyclohexyl methyl ether rather than cyclohexanol. Suggest a mechanism.
Step 1
This forms an intermediate organomercury compound. This can be represented as follows: \[ \text{Cyclohexene} + \text{Hg(OAc)}_{2} \rightarrow \text{Intermediate organomercury compound} \] Show more…
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