Question
Reaction of HBr with $(R)-3$ -methyl-3-hexanol leads to racemic 3 -bromo3-methylhexane. Explain. (EQUATION CAN'T COPY)
Step 1
This step converts the poor leaving group (OH-) into a good leaving group (H2O). The reaction can be represented as follows: \[ (R)-3\text{-methyl-3-hexanol} + HBr \rightarrow (R)-3\text{-methyl-3-hexanol}^{+} + Br^{-} \] Show more…
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