00:01
Okay, so problem 18, we got talewine, right, talewine, and it's reacting with br2 -f -e -b -r -3, okay? so what this is going to do is add a bromine atom, okay, to our talewine.
00:17
And we're told that this is going to end up with three possible products or three isomers.
00:24
And what i have down here are just benzene rinks.
00:27
So talurine is a methyl benzene, meaning it has one methyl group.
00:33
And what i want to do is to add that methyl group to our benzene rings.
00:38
Okay, so these benzene rings are here in advance, primarily because i'm not very good at drawing cyclic structures.
00:47
And second thing is to just not to waste time.
00:53
So we got methyl on benzene ring, and that's...
00:58
Is what toluene looks like and i'll do that to the other structures as well okay so we got ch3 on all of our benzene rings so we are adding a bromine atom okay and the question now is well where are we putting that okay are we putting it here here here right if we if you put it on this carbon it's going to be the same as putting it here okay that's just going to be the same molecule.
01:37
And if you put it on this carbon, that's identical to putting it here...