00:01
So we are given the following reaction and we want to try to understand that even though this proceeds via an sn2 reaction, why we still have the same stereochemistry.
00:12
We have no inversion of stereochemistry rather.
00:15
So looking at our nucleophile looks like a cyanide, which is a very strong nucleophile.
00:20
We know that this would occur via an s &2 reaction.
00:24
And so given the organic molecule on the far left here, we are given that it has s -stereoamylase.
00:30
Chemistry, but i want to go ahead and double check that so we can just assign priorities to our groups.
00:36
We see that our toscelet group is going to be prider number one, and then our carbon bound to our orthoxi group is going to be number two, and then we are going to have our methyl group as number three, and our hydrogen as number four.
00:51
So what we see is, is we're going in a, what looks to be in our configuration, however, we want our hydrogen to be going away from us.
00:58
So in reality, we do have an s configuration.
01:03
All right, so we can go ahead and now write the reaction and know what our product's going to look like.
01:07
So we can go ahead and write right here real quick that we know we're going to proceed being s &2, and our product is going to look like the following...