Problem

Using complete subshell notabreviations, $15^{2} …

07:10

Problem 47 Hard Difficulty

Read the labels of several commercial products and identify monatomic ions of at least six main group
elements contained in the products. Write the complete electron configurations of these cations and anions.

Answer

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Chemistry 101

Chemistry

Chapter 6

Electronic Structure and Periodic Properties of Elements

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Video Transcript

problem. 47 from top to six is asking us to identify six mon atomic ions and write their complete electron configuration. So it asks us to, um that we can find these mon atomic ions on commercial products. But I'm just gonna choose some arbitrarily. You are more than welcome to do so yourself, as long as we're choosing is an eye on. So it has a charge. So I'm gonna pick sodium and chloride table salt. I was gonna pick. I owe Dine. Also insult about some potassium that's in bananas and calcium And let's do you for the final one. Let's do bromide. Let's see. Okay, so now that we have selected Armand Atomic Ions, let's go to the periodic table and decipher our electron configuration. So this electron configuration table is in the textbook, and it's really helpful because it tells you the, um, the configuration of all the elements. Eso our 1st 1 is sodium, so you can see here that it occupies up to three s, and then there's a little one in the top right hand corner and that tells you how many electrons air in that show. So if we go back up to sodium and remember that it's in three us. So let's go back up to sodium and start writing out the configuration. So want us to us to pee. Three s one are not going to do all the super scripts for all of the electron shells just because, um, just to save some time. So notice that sodium is a cat eye on. So that means that he has Lawson Electron. So this three s one. Um, this electron has actually been lost because said I'm lost that last electron. So then we can actually go ahead and delete that three s one. And then we will add a superscript here to denote that this pea shell is full. Great. So let's go on to chlorine. Next, let's go down to our configuration table, and we see here that chlorine is in three p and it has five electrons in that three piece show, so let's go ahead and go. Go ahead. Sent one as to us to pee three s three p and you think it was five. Yes, maybe five. However, you noticed that chlorine is an an eye on, so it has gained an electron So it has gained an electron in this three p six orbital. So the superscript is actually going to change to a six? No, Like that superscript. There we go. And iodine, let's go to our configuration table. So iodine is down here It's in five p and also five electrons like chlorine. So let's go ahead and go one As to us to pee three US three p for us three D four p five s, four d and then we go into five p where I dinos and it is like chlorine. So it has five electrons and it's p orbital. However, because this isn't and I am just like chlorine, it actually is, has gained an extra electrons. So this five is actually going to be a six. Okay, let's move on to potassium. So potassium is four s, so we can go ahead and fill all those shells up until four s. So let's start with one as to as to pee three s. Think that was it? No. So we have three p and then four s and it has one electron, so we're gonna have a superscript of one. However, because potassium is a cat I own. It has actually lost that electron in the four s orbital, so we can actually go ahead and delete this and we're gonna add a six and the superscript note that it is a fool show. Okay, Calcium. So Caston was right next to potassium, so it's going to be very similar configuration, so we'll start out with one That's 21 as to us to p three s, three p for us. Superscript two. However, calcium is a cat eye on that has lost two elections. Hence it's two plus charge. So it, um, we can actually go ahead and get rid of these two electron in the four as orbital and I don't have the same configuration as potassium. Lastly, we have bromide. So bromide is in the same column as chlorine, and I don't. It is four p um, so we can actually go ahead and start that with the same configuration as I done and just end a bit. Really? So one as to us to p three s, three p for us, three D for P, and I believe yes, it's four p with a superscript of five. However, um, like chlorine and I dine. Romain has actually gained an electron. So this last p orbital is a full shell of electrons. So for P six, Um, I would just like to reiterate that I did not write the super scripts for the entire electron configuration just to save some time. But if for the correct notation, you need to indicate all the electrons in the previous sub shells

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