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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94 Problem 95 Problem 96 Problem 97 Problem 98 Problem 99 Problem 100 Problem 101 Problem 102 Problem 103 Problem 104 Problem 105 Problem 106 Problem 107 Problem 108 Problem 109 Problem 110 Problem 111 Problem 112 Problem 113 Problem 114 Problem 115 Problem 116 Problem 117 Problem 118 Problem 119 Problem 120 Problem 121 Problem 122

Problem 108 Hard Difficulty

Reading Blueprints. Find a polynomial that represents
a. the difference in the length and width of the one-bedroom apartment.
b. the perimeter of the apartment.

Answer

$x^{2}+a x$

Related Courses

Algebra

Elementary and Intermediate Algebra 5th

Chapter 5

Exponents and Polynomials

Section 5

Adding and Subtracting Polynomials

Related Topics

Exponents and Polynomials

Polynomials

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Watch More Solved Questions in Chapter 5

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46
Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
Problem 56
Problem 57
Problem 58
Problem 59
Problem 60
Problem 61
Problem 62
Problem 63
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Problem 65
Problem 66
Problem 67
Problem 68
Problem 69
Problem 70
Problem 71
Problem 72
Problem 73
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Problem 75
Problem 76
Problem 77
Problem 78
Problem 79
Problem 80
Problem 81
Problem 82
Problem 83
Problem 84
Problem 85
Problem 86
Problem 87
Problem 88
Problem 89
Problem 90
Problem 91
Problem 92
Problem 93
Problem 94
Problem 95
Problem 96
Problem 97
Problem 98
Problem 99
Problem 100
Problem 101
Problem 102
Problem 103
Problem 104
Problem 105
Problem 106
Problem 107
Problem 108
Problem 109
Problem 110
Problem 111
Problem 112
Problem 113
Problem 114
Problem 115
Problem 116
Problem 117
Problem 118
Problem 119
Problem 120
Problem 121
Problem 122

Video Transcript

So in this problem, we're given the blueprint of a house, which I droop a little bit off onto the right. I didn't put in all of the different rooms. I only put in the bedroom because reading the problem, that's the only specific room that we're going to be talking about. But I didn't put in all of the other measurements. So in part A, they're being asked to find the difference in the length versus the with off that one bedroom. Remember, difference means subtraction, so they want us to subtract the length fromthe with. So if we want to find the difference in the length in the length in the with. So in our bedroom, the length of it is for explosive tree, and the whiff of the bedroom is X squared minus six x plus tree. So if we want to find a difference between the length and the width, we simply need to subtract. Um, well are with is the quantity X squared minus six X plus three minus the length, which is four X plus three. Well, essentially, we just subtracting Paulino meals, so the terms in the first polynomial will just get brought down, so we'll have X squared minus six X plus three. And for the second polynomial, we simply need to change their signs. So the positive for X becomes negative for X and the positive three becomes negative three. And now we simply need to combine like terms. Well, you know this. The X Square does not have a late term so that we'll get brought down. Negative six x has a late term negative for ex Well, negative six x minus four X is negative 10 x and positive. Three has a late term in negative three. But those air gonna cancel each other out. So what we find is the difference between the length and the width is the quantity X squared minus 10 X Because our problem gives us units, we should use those in our final answer. So she also mentioned that it's a difference in feet now for part B. We're being asked to find the perimeter off the entire apartment. Well, to find perimeter, we essentially just need to add up all the side lips. Well, because it's a rectangle. The with is going to be this beat the same on both sides and the length will also be the same on both sides. So for part B to find the perimeter, essentially, we can do two times what we would get when we do the with, plus two times the length well, To find the whiff, we need to add three X plus one an X squared minus six X plus three. So we're gonna do two times the quantity of three X plus one, plus the quantity of X squared minus six X plus three. And then we're gonna add this to two times are length well, our length. We need to add X squared minus X plus six plus for explosive tree. So we'll have plus two times the quantity of X squared minus X plus six, plus the quantity of four X plus three. So now, looking within that first set of parentheses because we're adding, we simply need to combine like terms, so we will be left with two times the quantity off. Now let's find our light terms. Let's start with our ex Greater. It doesn't have a late term, so we just need to bring it down. Our next term is three bucks. Which life term is negative. Six X Well, three months. Six is negative. Three. So we'll have negative three X and then lastly, we have positive. One who's like term is positive three. So we'll get positive for now. We'll do the same thing for our life. We're gonna have plus two times. So again, we're gonna find our like terms. Well, X Square does not have a life term, so we'll have X squared are negative. X has a late term of positive for ex. Well, negative one plus fours. Positive three. So what? Positive Three X and six has a late term of three, while six plus three is not. So what? Positive night. So now I'm going to go on to a different screen just because I'm running out of room. So we're gonna have two times the quantity and I'm gonna keep scrolling back so I can remember it. We have X squared minus tree experts for plus two times are length, which we found to be X squared plus three X plus nine. And now we need to simplify this discretion. Well, first, we need to distribute the to teach term in both sets of prophecies, so I'm gonna multiply each of these terms by two. Well, two times X squared is two ex word. Two times negative. Three exes, negative six x and two times four is positive. A. I nail need to do the same thing for my second Senate prep. See, I need to distribute the two to each of those terms. Well, two times X squared is positive to X square two times three x is positive. Six x and two times nine is 18. And now we just need to combine our life terms. So let's start with two ex work. Well, it's like term is also to X word. Well, two plus two is four, so we'll be left with four x squared. Our next term is negative. Six. X Who's like term is positive? Six. Sex while negative six plus 60 So those terms will cancel each other row. Next, we have positive. Eight. Who's like charm is positive. 18. Well, eight plus 18 is 26. What? Plus 26. So now we've found an expression to represent the perimeter of the apartment. And because we're giving units, we should also give units in our answer, which in this case will be feet. So what we've found is DEA permit There would be for X squared 26 feet

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Alan S. Tussy, R. David Gustafson

Elementary and Intermediate Algebra 5th

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Additional Mathematics Questions
multiply-8-x-13-x-7

00:40

Multiply.
$$
(8 x-1)(3 x-7)
$$

find-each-special-product-5-b-22

00:45

Find each special product.
$$
(5 b-2)^{2}
$$

simplify-each-expression-if-possible-leftfrac2-s23-t5right5

01:49

Simplify each expression, if possible.
$$
\left(\frac{2 s^{2}}{3 t^{5}…

expand-each-binomial-see-example-3-ab3

01:14

Expand each binomial. See Example 3.
$$
(a+b)^{3}
$$

multiply-82-p-q2-p-q-3-p5-q

00:47

Multiply.
$$
8.2 p q(2 p q-3 p+5 q)
$$

a-student-was-asked-to-simplify-frac16-x2-3frac23-x2-explain-the-error-below

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A student was asked to simplify $\frac{1}{6} x^{2}-3+\frac{2}{3} x^{2}$. Exp…

divide-the-polynomial-by-the-monomial-see-example-2-frac4-x14-36-x836-x12

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Divide the polynomial by the monomial. See Example 2.
$$
\frac{4 x^{14…

multiply-9-x2leftx2-2-x6right

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Multiply.
$$
9 x^{2}\left(x^{2}-2 x+6\right)
$$

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A teacher is going to purchase a block of wax so that the children in her cl…

factor-25-m4-25

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Factor.
$$
25 m^{4}-25
$$

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