00:01
So in this problem, we're given the blueprint of a house, which i drew a little bit of onto the right.
00:07
I didn't put in all of the different rooms.
00:09
I only put in the bedroom because reading the problem, that's the only specific room that we're going to be talking about.
00:14
But i did put in all of the other measurements.
00:17
So in part a, they're being asked to find the difference in the length versus the width of that one bedroom.
00:23
Remember, difference means subtraction.
00:26
So they want us to subtract the length from the width.
00:30
So if we want to find the difference in the length, in the length, and the width.
00:47
So in our bedroom, the length of it is 4x plus 3, and the width of the bedroom is x squared minus 6x plus 3.
00:55
So if we want to find the difference between the length and the width, we simply need to subtract them.
01:01
Well, our width is the quantity, x squared, minus 6x plus 3, minus the length, which is 4x plus 3.
01:11
Well, essentially, we're just subtracting polynomials.
01:15
So the terms in the first polynomial will just get brought down.
01:18
So we'll have x squared minus 6x plus 3.
01:23
And for the second polynomial, we simply need to change their signs.
01:26
So the positive 4x becomes negative 4x, and the positive 3 becomes negative 3.
01:31
And now we simply need to combine light terms.
01:34
Well, you notice the x squared does not have a light term, so that will get brought down.
01:39
Negative 6x has a late term of negative 4x, well negative 6x minus 4x is negative 10x, and positive 3 has a late term of negative 3, but those are going to cancel each other out.
01:52
So what we find is the difference between the length and the width is the quantity x squared minus 10x.
01:59
Because our problem gives us units, we should use those in our final answer.
02:02
So she also mentioned that it's difference in fee.
02:07
Now for part b, we're being asked to find the perimeter of the entire apartment.
02:13
Well, to find perimeter, we essentially just need to add up all the side lengths.
02:17
Well, because it's a rectangle, the width is going to be the same on both sides, and the length will also be the same on both sides.
02:26
So for part b, to find the perimeter, essentially we can do two times what we would get when we do the width plus two times the length.
02:36
Well, to find the width, we need to add 3x plus 1 and x squared minus 6x plus 3.
02:42
So we're going to do 2 times the quantity of 3x plus 1 plus the quantity of x squared minus 6x plus 3.
02:55
And then we're going to add this to 2 times our length.
02:59
Well, our length, we need to add x squared minus x plus 6 plus 4x plus 3.
03:04
So we'll have plus two times the quantity of x squared minus x plus six plus the quantity of 4x plus three.
03:16
So now looking within that first set of parentheses, because we're adding, we simply need to combine like terms.
03:22
So we will be left with two times the quantity of.
03:26
Now let's find our light terms.
03:28
Let's start with our x squared term.
03:29
It doesn't have a like term, so we just need to bring it down.
03:33
Our next term is 3x, which light term is negative 6...