Recall that the differential equation for the instantaneous charge $q(t)$ on the capacitor in an $L R C$ -series circuit is
$$
L \frac{d^{2} q}{d t^{2}}+R \frac{d q}{d t}+\frac{1}{C} q=E(t)
$$
See Section 3.8. Use the Laplace transform to find $q(t)$ when $L=1 \mathrm{~h}, R=20 \Omega, C=0.005 \mathrm{f}, E(t)=150 \mathrm{~V}, t>0, q(0)=0$
and $i(0)=0$. What is the current $i(t) ?$