00:01
So here, the effect of varying the percent excess air during the steady flow process from 0 to 200 percent on the temperature at which 97 percent of carbon monoxide is burned.
00:20
So co2 is to be studied.
00:23
Now, to solve this problem, we need to give ees a guest value for t prop, a guest value for t prop.
00:33
Other than the default value of one.
00:36
So it should have a guess value other than one.
00:46
Now set the guess value of t -prod to 1 ,000 kelvin by selecting variable information in the options menu.
00:54
So first thing that you have to give is let's give t -prod.
01:00
If we're not proper product temperature to be 1 ,000 kelvin, using the variable info in options menu.
01:17
Now the input, you know, and then press f2 or click the calculator icon.
01:30
This is the first thing that we have to do.
01:33
Now after that, the input data from the diagram window gives you know percent excess is equals to 100.
01:47
So x is equal to 100.
01:48
Equals to percent excess divided by 100.
01:56
X equals to percent excess air divided by 100.
02:06
Then we get, sorry for the inconvenience course here.
02:24
So here we get free fraud, this pressure is equals to 101 .3 kilofascal ru equal to 8 .314 kilojou per kilo mole kelvin f equals to 0 .97.
02:50
So the combustion equation for stoichiometric amount of air, that is co plus 0 .502 plus 3 .76 and 2 equals to co2 plus co2 plus 0 .0 plus 0 .0 plus 0 .0 plus 0 .2 plus 0 .5 into 3 .76 nt.
03:15
Now considering this equation, for incomplete, it would be, the incomplete one, complete combustion, it would be co plus 1 plus ex into 0 .5 into 002 plus 3 .76 and 2...