0:00
Hi everybody.
00:02
So we need to find the initial pressure, the heat transfer, entry change, and the process.
00:07
Okay, so for this, we have argon.
00:14
So argon, and it's going to meet in the middle with the f thing.
00:32
Okay, so we need to do the energy equation.
00:36
So we have q1, 2, 2, which is, u t1 and this is going to give us n of the argon.
00:50
There we are.
00:50
I'm just going to put a.
00:53
Apparently, there we go, ar.
00:57
Okay.
00:58
Of u2 minus u1 plus n of ethane.
01:03
I'll just put e for ethane.
01:05
U2 minus one.
01:07
It must be ethane, so that's going to be argon.
01:10
Okay.
01:10
Okay.
01:12
And so this is thing equal to n -a -r of c -v -a -r of t2 minus t -a -r of a -r plus ethane times c -t of ethane.
01:30
T -t minus t -u of n -f -n.
01:34
Okay.
01:36
So now what we're going to do is find the in the number of moles for argon and that's just going to be 300 for the pressure times one for the volume and the r is going to be the generic r so 3145 that's a constant okay and the temperature is going to be 283 .15 and we get 0 .2 0 .1 274.
02:07
Color and gold.
02:10
And now we're going to have the end of the ethane, which is going to be 200 times 2, and the 2 to volume, 200 is the pressure, 8 .3145 for the constant, and the temperature is 3 -2, and the temperature is 3 -2 -3 .15, and we get 0 .148, 8, 4 more.
02:38
Okay.
02:40
And now we have n2 is equal to an a.
02:46
Argon plus the ethanol.
02:49
And it's going to be 0 .174 plus 0 .1488.
02:56
And we get 0 .2762kno.
03:05
And we need to find the pressure of.
03:08
Of 2, which is going to be into r2 divided by volume 2...