Reconsider the surface-catalyzed bimolecular reaction in Problem $29-55 .$ If $\mathrm{A}(\mathrm{g}$ ) and $\mathrm{B}(\mathrm{g})$ do not compete for surface sites, but instead each molecule uniquely binds to a different type of surface site, show that the rate law is given by
$$
v=\frac{k_{3} K_{\mathrm{A}} K_{\mathrm{B}}[\mathrm{A}][\mathrm{B}]}{\left(1+K_{\mathrm{A}}[\mathrm{A}]\right)\left(1+K_{\mathrm{B}}[\mathrm{B}]\right)}
$$