00:01
For this question, the scenario described with the stack of papers can basically be summarized as follows.
00:07
So we have some sequence, a, b, c, any permutation of these three letters.
00:16
And then for each transition, one of the letters gets selected and moved to the left.
00:24
So for example, b may be selected with probability b, in which case it's moved to the left.
00:34
So it transitions to b, a, c.
00:43
And x sub n represents the sequence after the nth transition.
00:51
So, for example, if this happened to be the third transition, then this sequence here would be x sub 3.
01:00
So for part a, we're told that the initial state is abc, and we're asked to determine the state space for this chain.
01:19
So if all letters of a, b, and c have non -zero probabilities of being selected to be the one moved to the left, then the state space is every permutation that's possible.
01:33
So we have a, b, c, a, c, b, a, c, b, a, c.
02:06
So that's part a.
02:07
And then for part b, we're told, again, if this is the initial state, what are the possibilities for the first state? the first transition.
02:22
So there's only three things that can happen here.
02:25
A will be selected, or b will be selected, or c will be selected.
02:36
So if a is selected, it remains on the left, and we end up with the same state.
02:43
If b is selected, it gets shifted to the left, and we end up with b, a, c.
02:49
And if c gets selected to the far left, and we end up with c, a, b.
02:57
These are the only three possible states for x, sub 1.
03:04
And the question also mentions is every arrangement listed in a possible.
03:09
So obviously not...