Question
Rectangular Coordinates to Polar Coordinates Convert the rectangular coordinates to polar coordinates with $r>0$ and$0 \leq \theta<2 \pi$. $$(-\sqrt{6},-\sqrt{2})$$
Step 1
We can do this by using the formula $r=\sqrt{x^2+y^2}$, where $x$ and $y$ are the rectangular coordinates. In this case, $x=-\sqrt{6}$ and $y=-\sqrt{2}$. So, we have $r=\sqrt{(-\sqrt{6})^2+(-\sqrt{2})^2}=\sqrt{6+2}=2\sqrt{2}$. Show more…
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