00:01
In the given problem there is a straight current carrying conductor.
00:10
This is the horizontal straight current carrying conductor which is carrying current towards left.
00:17
Let the current be high.
00:19
And then there is a rectangular loop made up of a conducting wire and this is the axis of this loop and the loop is oriented nearby this current carrying conductor in such a manner that its axis is at a distance of r from the straight current carrying conductor.
00:53
And then it is being taken away from this current carrying conductor with a velocity v.
01:00
Length of the loop rectangular loop is given as a small a here and its width is given as t first of all in the first part of the problem we have to find magnetic flux average magnetic flux due to this straight current connecting conductor which is linked through this rectangular loop so to find this magnetic flux linked through the coil we consider this rectangular loop to be made up of a large number of strips each having a differentially small width and then we choose one such strip differentially small strip having a width here suppose this is the differentially small strip this strip is at a distance of suppose it is its distance is x from the current carrying conductor and its width, differentially small width is x.
02:22
So length of the strip will be a only.
02:27
So differentially small area of the strip will be a.
02:43
D -a is equal to length into width.
02:46
Length is a and width we have assumed it to be d -a.
02:52
Now to find a magnetic flux linked through this strip, we will consider, we will find an expression for the magnetic field at the location of this strip which is at a distance of x from the current carrying conductor.
03:05
To magnetic field at the location of this small strip that is using by 10 severed law that magnetic field will be given by b is equal to mu not upon 4 pi to i by x the distance of the strip from the current gap connecting conductor.
03:42
Hence the small magnetic flux differentially small linked through this strip will be given by b5 is equal to b .a.
04:21
Here for a this will be da...