Question
Refer to Example 8.4 and suppose that $Y$ is a single observation from an exponential distribution with mean $\theta$ a. Use the method of moment-generating functions to show that $2 Y / \theta$ is a pivotal quantity and has a $\chi^{2}$ distribution with 2 df.b. Use the pivotal quantity $2 Y / \theta$ to derive a $90 \%$ confidence interval for $\theta$c. Compare the interval you obtained in part. (b) with the interval obtained in Example 8.4
Step 1
Step 1: The moment generating function (MGF) of an exponential distribution with mean $\theta$ is given by $M(t) = \frac{1}{1 - \theta t}$ for $t < \frac{1}{\theta}$. Show more…
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Refer to Exercise $8.46 .$ Assume that $Y_{1}, Y_{2}, \ldots, Y_{n}$ is a sample of size $n$ from an exponential distribution with mean $\theta$ a. Use the method of moment-generating functions to show that $2 \sum_{i=1}^{n} Y_{i} / \theta$ is a pivotal quantity and has a $\chi^{2}$ distribution with $2 n$ df. b. Use the pivotal quantity $2 \sum_{i=1}^{n} Y_{i} / \theta$ to derive a $95 \%$ confidence interval for $\theta$ c. If a sample of size $n=7$ yields $\bar{Y}=4.77$, use the result from part (b) to give a $95 \%$ confidence interval for $\theta$.
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Confidence Intervals
Suppose that the random variable $Y$ has a gamma distribution with parameters $\alpha=2$ and an unknown $\beta$. In Exercise 6.46 , you used the method of moment-generating functions to prove a general result implying that $2 Y / \beta$ has a $\chi^{2}$ distribution with 4 degrees of freedom (df). Using $2 Y / \beta$ as a pivotal quantity, derive a $90 \%$ confidence interval for $\beta$
Suppose that $Y_{1}, Y_{2}, \ldots, Y_{n}$ constitute a random sample of size $n$ from an exponential distribution with mean $\theta$. Find a $100(1-\alpha) \%$ confidence interval for $t(\theta)=\theta^{2}$.
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