00:01
So for a, we want to know what is the distance from sodium to its nearest neighbor? so in an ionic crystal lattice, the optionally charged ions are arranged next to each other.
00:14
The nearest neighbor of sodium ion is going to be the chlorine ion.
00:21
So we can see that it would be one half of a because based off of this drawing, the distance from the center of one ion to the neighboring ion is one half of the edge of unit cells.
00:38
Which is a cube.
00:40
So then we want to know how many equidistant nearest neighbors does sodium ion have.
00:45
So the equidistant neighbors are going to be the oppositely charged ions.
00:52
In this case, sodium has six neighbors and they're all chlorine.
00:58
So the reason is so the little atoms are the sodium and then we have one, two, three, four of them.
01:07
Then we have to take into account that if there's another unit cell attached to this one, we're going to actually have a chlorine that is from the other unit cell touching the sodium.
01:29
And there will be two from the other unit cell that will be touching it.
01:35
So you can imagine that the unit cells are like blocks stacked on top of one another.
01:47
And if we stack the next unicel on top of this one, we should get six chlorine atoms next to the sodium.
01:54
So now for the next one, we have to find the distance in terms of a from central to the center of sodium to the nearest sodium ion.
02:06
So if we look at only the sodium ions in the unit cell, they're in an fcc arrangement.
02:13
So i'm going to just draw this unicel with just the sodium ion.
02:17
Then we close up on one face of this unit cell, this is what we'll see.
02:23
We can see that we have a line going through the center of the ions in the corners.
02:31
And let's say that r is equal to the radius of one ion...