Refer to the following:
Recall that the derivative of $f$ can be found by letting $h \rightarrow 0$ in the difference quotient $\frac{f(x+h)-f(x)}{h} .$ In calculus we prove that $\frac{e^{h}-1}{h}=1,$ when $h$ approaches $0 ;$ that is, for really small values of $h, \frac{e^{h}-1}{h}$ gets very close to 1.
Use this information to find the derivative of $f(x)=e^{x}$