Question
Refer to the Integrative Example. In contrast to the Chernobyl accident, the 1979 nuclear accident at Three Mile Island released only 170 curies of $^{131} \mathrm{I}$ How many milligrams of $^{131}$ I does this represent?
Step 1
We need to convert the release of 170 curies of \(^{131}\mathrm{I}\) into milligrams. A curie is a unit of radioactivity, and we need to relate it to the mass of the substance. Show more…
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Refer to the Integrative Example. Another radioisotope produced in the Chernobyl accident was $^{137} \mathrm{Cs}$. If a $1.00 \mathrm{mg}$ sample of $^{137} \mathrm{Cs}$ is equivalent to 89.8 millicuries, what must be the half-life (in years) of $^{137} \mathrm{Cs} ?$
As a result of being exposed to the radiation released during the Chernobyl nuclear accident, the dose of iodine-131 in a person's body is $7.4 \mathrm{mCi}$ $\left(1 \mathrm{mCi}=1 \times 10^{-3} \mathrm{Ci}\right) .$ Use the relationship rate $=\lambda N$ to calculate the number of atoms of iodine- 131 to which this radioactivity corresponds. (The halflife of ${ }^{131} \mathrm{I}$ is 8.1 d. $)$.
As a result of being exposed to the radiation released during the Chernobyl nuclear accident, the dose of iodine-131 in a person's body is $7.4 \mathrm{mCi}$ $\left(1 \mathrm{mCi}=1 \times 10^{-3} \mathrm{Ci}\right) .$ Use the relationship rate $=\lambda N$ to calculate the number of atoms of iodine- 131 to which this radioactivity corresponds. (The half-life of $\left.^{131} \mathrm{I} \text { is } 8.1 \mathrm{d.}\right)$
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