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Refer to the position-versus-time plot in FIGURE $2-44$ for the following questions: (a) Is the average speed for the time interval between points 1 and 2 greater than, less than, or equal to the average speed for the time interval between points 1 and 3$?$ Explain. (b) Is the average velocity for the time interval between points 2 and 4 greater than, less than, or equal to the average velocity forthe time interval between points 3 and 4 ? Explain.

(a) Greater(b) Smaller

Physics 101 Mechanics

Chapter 2

One-Dimensional Kinematics

Motion Along a Straight Line

Cornell University

University of Michigan - Ann Arbor

Hope College

University of Winnipeg

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Okay, So in this problem, we have ah, lot off. Position versus time represents the movement of object or particle. We can see that this movement is similar to a horrible, horrible movement. So we can argue that this is accelerated movement and the problem wants us to compare if the average velocity let's put it this way. The average velocity between the 0.1 and two are greater. Smaller are equal. Then the velocity between the points one and three. Okay, so let's suppose that this movement represents a movement off the off object with constant acceleration. If so, we can say that the average velocity between two points is just hess off the lost much of the first point. Tell us velocity off this second point. Okay, so let's, uh, plight this concept to Arthur lost searches in here. We're going to have velocity of between points one into going to be feet one. Well, us too divided by two. And you are decidedly going to have if you want, plus victory divided by two. Okay, so first we need to understand that. Look into the graph. This part of the movement of the graph we have negative velocity view is it? Last stints Europe because we're moving backwards in position. But in this part of the movement, the velocity is bigger than zero. Because we're moving forward. That means that the average velocity here, this signal between view one and victory is going to be a minor sign because this too have opposite directions off movement. So if we suppose this we can say precisely that view one, let's ve to always will be greater than the one miner's Vetri because here we are adding something. You are here. We are taking something. So the answer to the first I tonight and a he is going to be great there. Then you won in victory and this tough process it's too holds Even if the acceleration was not constant because we can still apply devil aas it eas were still be the same. We still have a positive velocity from 4.3 in a negative velocity for 0.1 and two. So the second item were we going to do the same The second item We need to come there the velocities off points Ah, two and four with the velocities of points three or four OK, so using the same tough process, we're going to have velocity of two plus velocity or four divided by two. And here we have. They lost the gift. Three Poulos velocity or four divided by two. Same thing we have here. Philosophy between one and four is going to have a minor sign. So the velocity between the points one and two and four it's going to be less than develops. The average velocity off the points less then the velocities off points. 03 and four. We can put actually smaller, smaller, smaller than the average velocity between 0.3 and four. That's the final answer. Thanks for watching.

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