00:01
Hi, in the first part of this conceptual problem, we have to define time constant of a resistive and capacitive circuit, this rc circuit.
00:14
So, we can say time constant of an rc series circuit is the time.
00:34
In which the charge stored over the capacitor achieves a value equal to 63 % of the maximum charge to be stored over it.
01:17
Over it this is the first answer now in the second conceptual part we have to give a relation for the time constant in terms of capacitance and resistance so simply this is given as the product of capacitance of the capacitor and resistance of the resistor answer for the second conceptual part now in the third conceptual part we have to obtain an expression for the impedance of such a circuit in terms of its time constant and frequency and resistance.
01:59
Now as we know impedance is the net opposition offered by the cr circuit.
02:06
So this is a vector sum of capacity reactance x c and resistance are.
02:14
Now for capacity reactance we know this is 1 by 2, 5.
02:20
F c to the whole square plus r square so it may be given as a square root of 1 by 4 pi square f squared c squared plus r square now taking r square as a common out as there was no r square in the numerator so we write an square in denominator.
02:53
So this is 4 pi square f square, c square r square which we can write as c into r to the whole square plus one.
03:05
Now this r can be taken out of the root leaving behind 1 upon 4 pi square f square and for c r this is time constant tau having a whole square plus one so this is the answer for the third conceptual part now in the problem part in the numerical problem the value of the resistance is given as 18 om rms voltage is given to be 24 volt and the frequency the source is 380 hertz.
03:55
The time constant of this circuit is 3 .0 into 10 tish per minus 4 second.
04:02
So to find rms current, first of all, we find impedance using the formula which we have obtained in the third conceptual part...