00:01
In this problem, we have been given that a plus b plus c is equal to the zero vector.
00:08
And we have also been given the magnitudes of a, b, and c, and we need to determine the value of a .b plus a .c plus b .c plus b.
00:17
Now, for that purpose, let us consider the dot product of a plus b plus c with a plus b plus c.
00:28
So since a plus b plus c is equal to 0, so this will be the dot product of 0 .0, so this will be equal to 0.
00:40
And on the left -hand side, if we use the distributive property, we have a .a plus a dot b plus a dot b plus a plus b dot c plus b .a plus b .a plus b.
00:58
Dot c plus c .a plus c .a plus c .b plus c.
01:08
And this is equal to zero.
01:13
Now we can use the commutative law to rewrite b .a as a .b.
01:19
We can rewrite c .a as a .c.
01:25
And we can also rewrite c .d.
01:28
B as b .c.
01:30
And we can also is the square of the magnitude of a.
01:35
Also we have a .b plus a dot c.
01:42
We rewrite b .a as a .b.
01:46
B .b.
01:46
B .b is the square of the magnitude of b...