00:01
For this question, we are going to be using the most probable speed and also the root mean square speed.
00:09
So we have two formulas that we're dealing with.
00:12
And we want to compare, first of all, the most probable speed of root mean square speed for nitrogen at 25 degrees celsius.
00:18
So we need to convert the temperature to calvin.
00:23
So i add 273 to get the temperature in calvin.
00:28
You convert the molar mass to kilograms for mole, so divide the molar mass of nitrogen by 1 ,000 to get that in kilograms per mole.
00:38
Then apply the formulas.
00:40
So the value for r is 8 .314 jule over mole times k.
00:47
And that's because we want the units of the speed we get to be meters per second.
00:53
So be sure that you're using the correct value for r.
00:57
And then be sure that temperature is in kelvin, divided by the mole and mass in kilograms per mole.
01:06
Then we need to take the square root of that entire thing.
01:12
So for the next part, we're just going to use the other formula.
01:16
So the only difference is this is it's going to be a square root of 3rt divided by the mole and mass.
01:22
So we multiply by 3 instead of 2.
01:25
So we're just going to plug in the numbers.
01:39
And then we're going to get the root matrix.
01:42
Mean square speed.
01:57
So now for the next part, we have two diagrams, or we have a diagram, and we have two curves...