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Problem 23 Easy Difficulty

Regard $ y $ as the independent variable and $ x $ as the dependent variable and use implicit differentiation to find $ dx/dy. $
$ x^4y^2 - x^3y +2xy^3 = 0 $


$$x^{\prime}=\frac{d x}{d y}=\frac{-2 x^{4} y+x^{3}-6 x y^{2}}{4 x^{3} y^{2}-3 x^{2} y+2 y^{3}}$$

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