Question
Repeat Exercise 103 for the position function given by $x(t)=(t-1)(t-3)^{2}, 0 \leq t \leq 5$.
Step 1
The position function is given by $x(t)=(t-1)(t-3)^{2}$. So, the velocity function $v(t)$ is the derivative of $x(t)$, which is: \[v(t) = \frac{dx}{dt} = \frac{d}{dt}[(t-1)(t-3)^{2}]\] Show more…
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