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Repeat Exercise 15 for the following SVD of a $3 \times 4$ matrix $A :$$A=\left[\begin{array}{rrr}{-.86} & {-.11} & {-.50} \\ {.31} & {.68} & {-.67} \\ {.41} & {-.73} & {-.55}\end{array}\right]\left[\begin{array}{cccc}{12.48} & {0} & {0} & {0} \\ {0} & {6.34} & {0} & {0} \\ {0} & {0} & {0} & {0}\end{array}\right]$$\times\left[\begin{array}{rrrr}{.66} & {-.03} & {-.35} & {.66} \\ {-.13} & {-.90} & {-.39} & {-.13} \\ {.65} & {.08} & {-.16} & {-.73} \\ {-.34} & {.42} & {-.84} & {-.08}\end{array}\right]$

Note that $A=U \Sigma V^{T},$ so matrix $V$ in this decomposition is given trasposed,so $v_{3}, v_{4}$ are not columns but rows of given matrix.

Algebra

Chapter 7

Symmetric Matrices and Quadratic Forms

Section 4

The Singular Value Decomposition

Introduction to Matrices

Campbell University

McMaster University

Harvey Mudd College

Lectures

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In mathematics, the absolu…

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Find an SVD of each matrix…

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For the matrices in Exerci…

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in this proper. We have a single ability composition A because to you, Tom sigma time, sweetie, it's so, uh, the prat won the rink a in fact, the course to the rink off Magic Sigma and therefore the metric Seema Sigma wig. It's easy to see that it's written. It's rank equals to two for the part B. Um, since the rank off a course to two. So the column space off a equals equals to spend off. Um, you want in the YouTube in this case you want you to because to, um, the following vector Just the 1st 1st and second column off magics to you and these two vectors are also normal. That purpose and there for the non space of a you will be the spin off the three and the V four that's is in our single ability composition. The last component in this matrix multiplication will be re transpose. That means the non space off a will be the spin off the last two row in the metrics, the syrupy the following are two batters. So this is this other solutions to the to this problem

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