00:01
Alright, so in this problem we have the setup.
00:08
So this is the x -axis and this is the origin and this is x equal 0 .8 meters.
00:16
So we have a charge negative 4 nanoculombs at the origin and negative 5 nanoculums at this position.
00:27
So for part a, we want to find out the electric field at 3 points.
00:33
So, 0 .1, x equal 0 .2 meters.
00:38
So this is 0 .1.
00:41
And 0 .2, x equal 1 .2 meters, 0 .2.
00:49
And 0 .3, x equal negative 0 .2 meters.
00:55
This is 0 .3.
00:56
So at 0 .1, the magnitude of the electric field is, well, here we just consider the, we also consider the 3.
01:08
Of the electric field.
01:09
It's 1 over 4 pi epsilon times.
01:14
So this is 0 .1 and this, the charge here and the charge there, the two charges, they are both negative.
01:26
So the electric field at this point induced by this one is pointing to the left and induced by this one is pointing to the right.
01:35
So we have negative 4 nanoculums divided by 0 .2.
01:40
Squared plus 5 nanoculum divided by 0 .6 squared...