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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61

Problem 21 Easy Difficulty

Repeat Exercise 2.20 using an element that has three naturally occurring isotopes.

Answer

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Chemistry 101

Chemistry

Chapter 2

Atoms, Molecules, and Ions

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Problem 16
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Problem 21
Problem 22
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Problem 25
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Video Transcript

Let's repeat exercise 2.20 using an element that has three naturally occurring isotopes on the element will choose here. We're going to choose the element oxygen as oxygen has three naturally occurring isotopes for part aid, and we'll use the isotopes. Vet simulator will select oxygen, and we'll write symbols of the isotopes of oxygen that air naturally occurring. Insignificant amounts, which will be oxygen 16, oxygen 17 and oxygen 18. And that, uh, those would be the three naturally occurring isotopes of oxygen for B or asked to predict the relative amounts or percentages of each of these isotopes found in nature. If we look up the average atomic mass for oxygen on our periodic table, will find that it is equal to 16.0 atomic mass units. Therefore, I would suggest that we would have I'm for oxygen 16 kind of 99.9% oxygen 16 and Oxygen 17 would be present, um, in a very small percentage, less than 0.1% and oxygen 18 would be very much less than 180.1%. As we increase the mass number for isotopes, the abundance get smaller, so I would predict some very small numbers for ox isotopes, auctions in 17 and oxygen 18 for part C. Let's make this mixtures. So I mean, I had lots of oxygen. 16 thio the simulation. But I'll go ahead and do that and I will take a picture of this. Once I've created it, I'm gonna add an oxygen 17 and an oxygen 18 to this mix. Mostly oxygen 16. And I would suggest that a picture would look something like this for part D. Let's reveal the percent composition and average atomic mass of what I have created here. And take a picture of this. Yeah. So, based on what I've created here, um, my percent composition is for oxygen 16, 83.3%. Oxygen 17 and oxygen 18 are both 8.3% each. And this works out to 16.24 562 atomic mass units on. If we compare this to my prediction in part B, this is not close. So this is not close to my prediction in part B. So let's go ahead and fix this and make it matches best we can, so we want kind of 99% oxygen. Um oxygen 16 and a Z best we can. If I can fix this, this will look like this here. So fixing it, I'm able to get 1998% oxygen 16. And I'm a little bit closer on the average atomic mass here, so we tried to adjust it. Aziz best we can. And for E. Let's go ahead and select the nature's mix here and when we select nature's mix, um so nature's mix here, which is the natural mixture, we find that we have 99 point 757% oxygen 16 on point 038 of a percent of oxygen 17 and point to 05% of oxygen. 18. So I was actually incorrect. I thought Oxygen 18 would be less than oxygen 17. Um, and I was incorrect there. And the atomic mass unit is 15 99940 atomic mass units. So it's like the under 16 and ah, gesture amounts to make them Aske Llosa's possible. We can't match that on the simulation doesn't let me get down to those small decimal places, but let's show what this nature's mixed looks like on the screen in the simulation the nature's mix would look something like this year well, at that picture in on the end here. So here would be the nature's mix what we can see, the actual percent composition and average atomic mass for oxygen. What?

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