00:01
In this question we're going to be making reference to exercise 9 where we've got our lambda 1 being equal to 0, giving us an x1 that is equal to 1 over root of 2, 1.
00:12
We also have our lambda 2 being equal to 3 root of 3, giving us an x2 that is equal to half of 1 root of 2 1.
00:24
And finally we've got our lambda 3 being equal to negative.
00:28
This is actually 3 root of 2, negative 3 root of 2, giving us an x3 that is equal to half of 1 negative root of 2 and 1.
00:41
Now that we have this, we have our x corresponding x is going to be 1 over root of 2, 1 over 2, 1 over 2, 0 over 2, 1 over 2, 0 over 2, 1 over 2 2, 1 over root of 2, 2, negative 1 over root of 2, 2, and we have in the 3rd row, having negative 1 over root of 2, 1 over 2 and 1 over 2...