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Repeat Exercise 3 with the pairs of metals here.a. copper and tinb. silver and aluminumc. copper and lead
a. $C_{u^{2}}+S_{n} \rightarrow C_{u}+S_{n}{ }^{2 t}$b. $3 A_{y}^{+}+A l \rightarrow A I^{3+}+3 A_{y}$c. $C_{u}^{2+}+P_{b}-7 P_{b}^{2+}+C_{4}$
Chemistry 102
Chemistry 101
Chapter 21
Controlling Energy
Section 5
Electrochemical Cell
Thermodynamics
Thermochemistry
Drexel University
University of Maryland - University College
Brown University
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question. Number four is a repeat of what we did in question number three, but now for three different electrochemical cells instead of just the one with calcium and iron. But the idea is to draw the structure or draw the electrochemical cell, and then identify what half reactions air occurring at each electrochemical cell. Identify what is oxidized and what is reduced and then right. The Net Ionic equation for the entire electrochemical cell. So for the first one, we have copper and tin. We go toothy activity, Siri's and we find out 10 is higher on the activity Siri's so it will be oxidized. Electrons will leave the tin and go to the copper, which is lower on the activity. Siri's. So if electrons were leaving the tin than tin is being oxidized, tin is going to tin two plus giving off the electrons and copper. Two plus is accepting the electrons to become copper solid, so we have copper, two plus and zinc. I'm sorry tin as theme, reactant and then copper solid and tin two plus as the products. The next one is silver and aluminum. Aluminum is higher up on the activity Siri's, so it will be oxidized and electrons will leave the aluminum and go to the silver if electrons air. Leaving aluminum than aluminum is becoming three plus in order to give up. Three electrons and silver is taking on the electrons to become silver Solid. Aluminum is oxidized, silver is reduced. The entire reaction then is silver plus, with aluminum going to silver solid plus aluminum three plus. And then we need a balance it to make sure we have a three plus charge on both sides. So we'll put a three here, so we have three plus, which will require us to put a three on our silver over here. The last one, then is copper combined with lead. Lead is higher on the activity. Siri's so electrons will leave the lad and go towards the copper lead, then is going to be oxidized so that it can have electrons. Leave it and then copper two plus is going to be reduced as it takes on those electrons to become copper solid, and the entire reaction is copper two plus plus lead solid going to copper solid plus lead two plus
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